http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/ Dedicated to the mathematical arts. Mon, 08 Sep 2008 03:44:09 +0000 http://wordpress.org/?v=2.5.1 http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59633 Bernardo Wed, 09 Apr 2008 12:37:16 +0000 http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59633 Nice proof, and It can be modified in order to work in the complex case. Nice proof, and It can be modified in order to work in the complex case.

]]> http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59387 Walt Thu, 20 Mar 2008 04:52:08 +0000 http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59387 I wondered if this was the original proof: it has a very classical flavor. I wondered if this was the original proof: it has a very classical flavor.

]]> http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59249 me Fri, 07 Mar 2008 18:34:10 +0000 http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59249 See Lax's Linear Algebra proof of the same. See Lax’s Linear Algebra proof of the same.

]]> http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59143 t8m8r Fri, 29 Feb 2008 06:01:10 +0000 http://www.arsmathematica.net/archives/2008/02/28/cauchy-schwartz-theorem/#comment-59143 It is nice. I read somewhere that it is exactly the way Schwarz proved it. Actually you don't need the full-blown linear algebra; there is the concept of discriminant for quadratic equations which is the same as your 2x2 determinant. It is nice. I read somewhere that it is exactly the way Schwarz proved it. Actually you don’t need the full-blown linear algebra; there is the concept of discriminant for quadratic equations which is the same as your 2×2 determinant.

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